3(4x^2+20x+10)=30

Solution for 3(4x^2+20x+10)=30 equation:

3(4x^2+20x+10)=30

We move all terms to the left:

3(4x^2+20x+10)-(30)=0

We multiply parentheses

12x^2+60x+30-30=0

We add all the numbers together, and all the variables

12x^2+60x=0

a = 12; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·12·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*12}=\frac{-120}{24}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*12}=\frac{0}{24}
=0
$